c program to count the number of odd and even digits in an integer

http://stackoverflow.com/a/38181488/6393408

#include<stdio.h> 
#include<conio.h>

void main()

{    

       int nodd,neven,num,digit ; 
       clrscr();



       printf("Count number of odd and even digits in a given integer number ");

       scanf("%d",&num);

                nodd = neven =0; /* count of odd and even digits */

                while (num> 0)

                    {

                        digit = num % 10; /* separate LS digit from number */

                        if (digit % 2 == 1)

                           nodd++;

                        else neven++;

                               num /= 10; /* remove LS digit from num */

                    }

                        printf("Odd digits : %d Even digits: %d\n", nodd, neven);

                        getch();